x^2+(3/4x)^2=68^2

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Solution for x^2+(3/4x)^2=68^2 equation: 



x^2+(3/4x)^2=68^2

We move all terms to the left:

x^2+(3/4x)^2-(68^2)=0



Domain of the equation: 4x)^2!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

x^2+(+3/4x)^2-68^2=0

We add all the numbers together, and all the variables

x^2+(+3/4x)^2-4624=0

We multiply all the terms by the denominator


x^2*4x)^2+(-4624*4x)^2+3=0

Wy multiply elements

4x^3-18496x=0

We do not support expression: x^3

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